# #19 Python Tutorial for Beginners | If Elif Else Statement in Python

///#19 Python Tutorial for Beginners | If Elif Else Statement in Python
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Learn Python Programming by Python Tutorial with examples
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In this video we will see:
– Conditional statements
– If statement
– Else statement
– Debugging code
– Nested if
– elif and else statement

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By |2019-08-05T21:49:42+00:00August 5th, 2019|Python Video Tutorials|40 Comments

### 40 Comments

1. Erratic Savage August 5, 2019 at 9:49 pm - Reply

x = int(input("Enter 1st no"))
y = int(input("Enter 2nd no"))
z = int(input("Enter 3rd no"))
if x>y>z:
print("1st no is the greatest no")
elif y > x > z:
print("2nd no is the greatest no")
elif z > y > x:
print("3rd no is the greatest no")

2. Ashwin Wilson August 5, 2019 at 9:49 pm - Reply

in which program u r typing these codes?

3. varun krishna kyathanpally August 5, 2019 at 9:49 pm - Reply

x = input("enter 1st numbr")

y = input("enter second numbr")

z = input ("enter third numbr")

if x > y and x > z:

print (x, "is the greatest")

if y > x and y > z:

print (y, "is the greatest")

else:

print (z, "is the greatest")

4. Pavan Mudhole August 5, 2019 at 9:49 pm - Reply

x=int(input("Enter the first numbern"))

y=int(input("Enter the second numbern"))

z=int(input("Enter the third numbern"))

if x>y and x>z:

print('x is greater '+str(x))

elif(y>x and y>z):

print('y is greater '+str(y))

elif (z>x and z>y):

print('z is greater '+str(z))

5. Rajesh Rayudu August 5, 2019 at 9:49 pm - Reply

x=2

y=3

z=4

a=[x,y,z]

max(a)

6. Rajesh Rayudu August 5, 2019 at 9:49 pm - Reply

x=0

if x>0:

print('x is positive number')

elif x<0:

print('x is a negative number')

else:

print('x is neutral number')

7. gunit panch August 5, 2019 at 9:49 pm - Reply

You r really so good teacher
Very funy style . I really like your style.
Thanks sir. I'm grateful.

8. arslan kabeer August 5, 2019 at 9:49 pm - Reply

Question#1
x = float(input("enter a number: "))

if x<0:

print("Negative number")

elif x>0:

print("Positive number")

else:

print("You enter the wrong input")
Question#2
y = int(input("enter 2nd number: "))

z = int(input("enter 3rd number: "))

if x>y and x>z:

print("1st is greater")

elif y>x and y>z:

print("2nd is greater")

elif z>x and z>y:

print('3rd is greater')

else:

print("Wrong input")

9. Tagir Tagirov August 5, 2019 at 9:49 pm - Reply

Why you speak with Indian accent?

10. Navaf KP August 5, 2019 at 9:49 pm - Reply

X = int(input("Enter Your 1st Number))
Y = int(input("Enter Your 2nd Number))
Z = int(input("Enter Your 3rd Number))

#here we have to use if elif statement as per the topic. So,

If x>y>z>:
print (x)
elif y>x>z>:
print(y)
else:
print(z)

Hope it will help

11. Srikar gosike August 5, 2019 at 9:49 pm - Reply

If a>=2 && a<=5: is this possible in if case or not

12. Srinivas Ramachandran August 5, 2019 at 9:49 pm - Reply

x=int(input('enter the first number'))

y=int(input('enter the seconds number'))

z=int(input('enter the third number'))

if(x==y==z):

print('all the values are equal')

elif((x>y)and(x>z)):

print('x was higher')

elif((y>x)and(y>z)):

print('y was higher')

else:

print('z was higher')

13. poison brother August 5, 2019 at 9:49 pm - Reply

awesome!!!
Last one elif also you missed ":". lol

14. Rajput Kailash August 5, 2019 at 9:49 pm - Reply

1st exercise;
x=int(input("enter a number"))
if(x>0):
print("x is positive")
else:
print("x is negative")

2nd exercise;

x=int(input("a="))
y=int(input("b="))
z=int(input("c="))
if(x>y & x>z):
print("a is greatest")
elif(x<y & y>z):
print("b is greatest")
else:
print("c is greatest")

15. Suvarna Malepati August 5, 2019 at 9:49 pm - Reply

Sir..In if condition, print (bye)is it must and should?? could you please tell me..sir

16. Suraj Pandey August 5, 2019 at 9:49 pm - Reply

Bhaiya there is problem facing use if and else if in idle

17. Abhinav verma August 5, 2019 at 9:49 pm - Reply

x = int(input("1st number: "))

y = int(input("2nd number: "))

z = int(input("3rd number: "))

a = [x,y,z]

print("The greatest number is",max(a))

18. Riyaz mhd August 5, 2019 at 9:49 pm - Reply

3rd way,
Simplest way
x,y, z=int(input("1st num")), int(input("2nd num")), int(input("3rd num"))
a=max(x, y, z)
print(a, "is big")
If any error in these 3 methods kindly comment

19. Riyaz mhd August 5, 2019 at 9:49 pm - Reply

2nd way,
x=int(input("1st num"))
y=int(input("2nd num"))
z=int(input("3rd num"))
If x>y and x>z:
print(x, "is big")
elif y>x and y>z:
print(y, "is big")
else:
print(z, "is big")

20. Riyaz mhd August 5, 2019 at 9:49 pm - Reply

There are 3 ways for the 2nd qstn
1.x=int(input("1st num"))
y=int(input("2nd num"))
z=int(input ("3rd num"))
if x>y:
if x>z:
print(x, "is big")
else:
print(z, "is big")
elif y>z:
print(y, "is big")
else:
print (z, "is big")

21. AAkil Ahmed August 5, 2019 at 9:49 pm - Reply

hats off sir! you are awesome..love you from Bangladesh

22. AI August 5, 2019 at 9:49 pm - Reply

who's here in 2019

23. Darshan Athihally August 5, 2019 at 9:49 pm - Reply

Thanks a lot Telsuko. My project was not working and now I understood why.

24. Aparna Sathiya August 5, 2019 at 9:49 pm - Reply

For even and odd nos u have used but while saying u said modulo % but by using itself u got the value how?

25. Pallavi Charnalia August 5, 2019 at 9:49 pm - Reply

Thankyou sir u teach very well 👍👌👌nice work done by u make some videos on PHP

26. Seth Akantey August 5, 2019 at 9:49 pm - Reply

Why are you guys using int. instead of float.? Cos ur client may enter 3.2, a decimal???

27. nikhil hp August 5, 2019 at 9:49 pm - Reply

do we have switch statement in python

please reply

28. Bilal Iqbal August 5, 2019 at 9:49 pm - Reply

from math import pow,sqrt

x=range(1,501)

for i in x:

if(sqrt(i)%2==1 or sqrt(i)%2==0):

print(i)

29. Bilal Iqbal August 5, 2019 at 9:49 pm - Reply

x=int(input("enter 1st no "))

y=int(input("enter 2nd no "))

c=int(input("enter 3rd no "))

if x<y:

x=y

if x<c:

x=c

print('the greatest no is 3rd '+str(x))

else:

print('the greatest no is 2nd '+str(x))

elif x<c:

x=c

print('the greatest no is 3rd '+str(x))

else:

print('the greatest no is 1st '+str(x))

30. Harman Deep August 5, 2019 at 9:49 pm - Reply

x=int(input("enter a value to find out negative or positive:"))

if x>0:

print("positive")

else:

print("negative")

31. kar theek August 5, 2019 at 9:49 pm - Reply

1.x = int(input("enter"))

if x > 0:

print("positive")

elif x < 0 :

print("negative")

else:

print("zero")

2.a = int(input("Enter 3 number: "))

result = [int(i) for i in str(a)]

print(max(result))

32. Nischal Bikram Bhandari August 5, 2019 at 9:49 pm - Reply

1 ==
x = int(input("enter any number"))
if x < 0:
print("negative")
elif x ==0:
print("zero")
else:
print("positive")
2==
x = int(input("enter any number"))
y = int(input("enter any number"))
z = int(input("enter any number"))
if x > y and x>z :
print("x is the greatest number")
elif y>x and y> z:
print("y is greatest number")
elif z > y and z > x :
print("z is the greatest number")

33. Ali Shaan August 5, 2019 at 9:49 pm - Reply

n1 = int(input("Enter 1st Number :"))

n2 = int(input("Enter 2st Number :"))

n3 = int(input("Enter 3st Number :"))

if n1 > n2 and n1 > n3:

b = str(n1)

print(b + " Is Greatest Number ")

elif n2 > n1 and n2 > n3:

b = str(n2)

print(b + " Is Greatest Number ")

elif n3 > n1 and n3 > n2:

b = str(n3)

print(b + " Is Greatest Number ")

else:

print("Wrong input")

34. Ali Shaan August 5, 2019 at 9:49 pm - Reply

a = int(input("Enter a number"))

if a >= 0:

b = str(a)

print(b + " is a Positive number ")

else:

print("Negative Number ")

35. RAJAN AGARWAL August 5, 2019 at 9:49 pm - Reply

This is the simplest way I think to solve 2nd

A=int(input("ist no")
B=int(input("2nd no")
C=int(input("3rd no")
R=A
If(R<B)
R=B
If(R<C)
R=C
Print(R, " is the greatest integer")

36. vinod kumar August 5, 2019 at 9:49 pm - Reply

while True:

try:

x = int(input("Enter a number: "))

break

except ValueError:

print("Please enter a valid number")

n = x % 2

if n==0:

print("The number you have entered " + str(x) + " is even number")

else:

print("The number you have entered " + str(x) + " is odd number")

37. Mona rockstar August 5, 2019 at 9:49 pm - Reply

Finally my doubt gets clarified about this #if,#elif,#else#Best Programmer#…

38. M_R_ . _H_A_P_P_Y August 5, 2019 at 9:49 pm - Reply

its really useful fo r me. thanks a lot

39. Garikapati Gopi chowdary August 5, 2019 at 9:49 pm - Reply

X=int(input()
If(x>0):
Print("positive number");
else:
Print ("negative number");

40. jr. TONY STARK August 5, 2019 at 9:49 pm - Reply

you are the greatest one sir you are amazing , there no any channel like this sir . thanks for your such kind help.
you explains every basic stuff and becoz of that we are becoming good in python. not only in python in all other language toooooo.
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